Zinc liberates hydrogen gas when reacted with dilute hydrochloric acid, whereas copper does not. Explain why?
Ans.
(i) Zinc reacts with hydrochloric acid to liberate Hydrogen gas as Zn is more reactive than Hydrogen and hence, displace it.
Copper is less reactive then Hydrogen and hence cannot displace it.
Hence, Zinc liberates hydrogen gas when reacts with dilute hydrochloric acid, whereas copper does not.
Hence, Zinc liberates hydrogen gas when reacts with dilute hydrochloric acid, whereas copper does not.
Zn>H>Cu
(ii) to avoid the photochemical reaction the silver chloride is placed in dark coloured bottles.
Ca(OH)2+Cl2 → CaOCl2
bleaching powder is kept open in air. ... If bleaching powder is held exposed in the air, it reacts with carbon dioxide (CO2) from the atmosphere to produce calcium carbonate (CaCO3) and chlorine gas (Cl2).
Q. A metal 'X' combines with a non-metal 'y' by the transfer of electrons to form a compound Z.
(i) State the type of bond in compound Z.
(ii) What can you say about the melting point and boiling point of compound Z?
(iii) Will this compound dissolve in kerosene or petrol?
(iv) Will this compound be a good conductor of electricity?
Ans.
(i) Ionic Bond
(ii) High
(iii) No
(iv) Yes
Q An element placed in the 2nd group and third period of the periodic table burns in the presence of oxygen to form a basic oxide.
(a)identify the element
(b)write the electronic configuration
(c)write a balanced equation when it burns in the presence of air
(d)write a balanced equation when this oxide is dissolved in water
(e)draw electron dot structure for the formation of this oxide
ANSWER
(a) Magnesium
(b) 2, 8, 2
(c)
(d)
(e) Electron dot structure for the formation of magnesium oxide is shown in image:
Zinc liberates hydrogen gas when reacted with dilute hydrochloric acid, whereas copper does not. Explain why?
sport formation in rhizopus
should the resistance of an ammeter be high or low give reason
The resistance of an ammeter should be low. An ammeter has to be connected in series with the circuit to measure current.
Post a Comment
Post a Comment